(1/(1+3i))+(1/(1+3i)^2)

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Solution for (1/(1+3i))+(1/(1+3i)^2) equation: 


D( i )

(3*i+1)^2 = 0

3*i+1 = 0

(3*i+1)^2 = 0

(3*i+1)^2 = 0

3*i+1 = 0 // - 1

3*i = -1 // : 3

i = -1/3

3*i+1 = 0

3*i+1 = 0

3*i+1 = 0 // - 1

3*i = -1 // : 3

i = -1/3

i in (-oo:-1/3) U (-1/3:+oo)

1/(3*i+1)+1/((3*i+1)^2) = 0

(1*(3*i+1))/((3*i+1)^2)+1/((3*i+1)^2) = 0

1*(3*i+1)+1 = 0

3*i+2 = 0

(3*i+2)/((3*i+1)^2) = 0

(3*i+2)/((3*i+1)^2) = 0 // * (3*i+1)^2

3*i+2 = 0

3*i+2 = 0 // - 2

3*i = -2 // : 3

i = -2/3

i = -2/3

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